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16t^2-44t=0
a = 16; b = -44; c = 0;
Δ = b2-4ac
Δ = -442-4·16·0
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1936}=44$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-44)-44}{2*16}=\frac{0}{32} =0 $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-44)+44}{2*16}=\frac{88}{32} =2+3/4 $
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